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TMUA Triangle Trigonometry and Radians

Trigonometry in triangles and sectors turns lengths and angles into equations. Radians make arc length and sector area simple formulas.

Paper 1 and Paper 2 topic. Specification codes: MM4.1, MM4.2, M5.16, M5.18. Last checked 12 November 2026.

Triangle rules

  • Sine rule: asin⁡A=bsin⁡B\dfrac{a}{\sin A}=\dfrac{b}{\sin B}.
  • Cosine rule: a2=b2+c2−2bccos⁡Aa^2=b^2+c^2-2bc\cos A.
  • Area =12absin⁡C=\tfrac12ab\sin C.

Radians

π\pi radians is 180∘180^\circ. For an angle θ\theta in radians, arc length is rθr\theta and sector area is 12r2θ\tfrac12r^2\theta.

Segments

A segment is a sector minus a triangle: area =12r2(θ−sin⁡θ)=\tfrac12r^2(\theta-\sin\theta).

Exact values and checks

Use exact values: sin⁡30∘=12\sin30^\circ=\tfrac12, cos⁡60∘=12\cos60^\circ=\tfrac12, sin⁡45∘=22\sin45^\circ=\tfrac{\sqrt2}2, sin⁡60∘=32\sin60^\circ=\tfrac{\sqrt3}2 and tan⁡45∘=1\tan45^\circ=1. Remember π6=30∘\tfrac\pi6=30^\circ, π4=45∘\tfrac\pi4=45^\circ and π3=60∘\tfrac\pi3=60^\circ.

Sketch every triangle. In 3D, find a right-angled triangle inside the solid first, then use SOH CAH TOA or Pythagoras.

The ambiguous case arises when you know two sides and an angle that is not between them. The sine rule can then give two possible angles, θ\theta and 180∘−θ180^\circ-\theta, and you must test whether both fit in a triangle.

For a sector, always check that the angle is in radians before using rθr\theta or 12r2θ\tfrac12r^2\theta, and give answers in terms of π\pi where the question allows.

Worked examples

Example 1

A triangle has sides 5 and 8 enclosing an angle of 60∘60^\circ. Find the third side and the area.

Show the worked solution

c2=25+64−2⋅5⋅8⋅12=49c^2=25+64-2\cdot5\cdot8\cdot\tfrac12=49, so c=7c=7. Area =12⋅5⋅8⋅32=103=\tfrac12\cdot5\cdot8\cdot\tfrac{\sqrt3}2=10\sqrt3.

Answer: Side 77, area 10310\sqrt3

Example 2

A sector has radius 6 and angle π3\tfrac\pi3. Find its arc length and area.

Show the worked solution

Arc length =6⋅π3=2π=6\cdot\tfrac\pi3=2\pi. Area =12⋅36⋅π3=6π=\tfrac12\cdot36\cdot\tfrac\pi3=6\pi.

Answer: Arc 2π2\pi, area 6π6\pi

Example 3

A circle of radius 4 has a chord that subtends an angle π2\tfrac\pi2 at the centre. Find the area of the minor segment.

Show the worked solution

Area =12⋅16(π2−sin⁡π2)=8(π2−1)=4π−8=\tfrac12\cdot16\left(\tfrac\pi2-\sin\tfrac\pi2\right)=8\left(\tfrac\pi2-1\right)=4\pi-8.

Answer: 4π−84\pi-8

Common mistakes

  • Using the sector formulas with an angle in degrees.
  • Using the cosine rule with the angle not between the two known sides.
  • Forgetting the ambiguous case when using the sine rule to find an angle.
  • Giving the sector area for a segment question.

Test yourself on this topic with our free practice questions.

Quick answers

How do you convert degrees to radians?

Multiply by π180\tfrac\pi{180}. For example 90∘=π290^\circ=\tfrac\pi2.

When do you use the sine rule instead of the cosine rule?

Use the sine rule when you have an angle and its opposite side. Use the cosine rule for two sides and the included angle, or three sides.

What is the formula for arc length?

rθr\theta, with θ\theta in radians.

Practise it under timed conditions

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